(4d-4)(3d-2)=12d^2+d+8

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Solution for (4d-4)(3d-2)=12d^2+d+8 equation: 



(4d-4)(3d-2)=12d^2+d+8

We move all terms to the left:

(4d-4)(3d-2)-(12d^2+d+8)=0

We get rid of parentheses

-12d^2+(4d-4)(3d-2)-d-8=0

We multiply parentheses ..

-12d^2+(+12d^2-8d-12d+8)-d-8=0

We add all the numbers together, and all the variables

-12d^2+(+12d^2-8d-12d+8)-1d-8=0

We get rid of parentheses

-12d^2+12d^2-8d-12d-1d+8-8=0

We add all the numbers together, and all the variables

-21d=0

d=0/-21

d=0

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